How much heat is needed to melt 1.6 kg of ice at 0 °C?

During a change of state the temperature stays the same while heat goes in or comes out: the latent heat. $Q = mL$, with $L_f = 3.34 \times 10^{5}\ \text{J/kg}$ to melt ice and $L_v = 2.26 \times 10^{6}\ \text{J/kg}$ to boil water. To warm water, $Q = m \times 4180\ \text{J/(kg}\,^\circ\text{C)} \times \text{(the rise)}$.