EasyChemistryHigh School (11–12)Organic Compounds with Functional GroupsConceptual

Give the IUPAC name of each compound. CH₃CH₂CH(CH₃)COOH; HOOC-CH₂-CH₂-CH₂-COOH; C₆H₅CH₂COOH…

Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

Give the IUPAC name of each compound.

$\text{CH}_{3}\text{CH}_{2}\text{CH}(\text{CH}_{3})\text{COOH}$
$\text{HOOC}\text{-}\text{CH}_{2}\text{-}\text{CH}_{2}\text{-}\text{CH}_{2}\text{-}\text{COOH}$
$\text{C}_{6}\text{H}_{5}\text{CH}_{2}\text{COOH}$
$\text{CH}_{3}\text{CH}(\text{OH})\text{COOH}$
$\text{ClCH}_{2}\text{CH}_{2}\text{COOH}$
$\text{CH}_{2}{=}\text{CHCOOH}$
$\text{CH}_{3}\text{CH}_{2}\text{CH}_{2}\text{CH}_{2}\text{COOH}$
$\text{HOOC}\text{-}\text{CH}_{2}\text{-}\text{COOH}$

Need a reminder? The key ideaShow

The carboxyl carbon is carbon 1. Acids come from oxidation of primary alcohols, aldehydes and alkylbenzenes (a benzylic hydrogen is needed), from hydrolysis of nitriles, amides and esters, and from RMgX with CO $_2$ , which adds one carbon. Two hydrogen bonds join acid molecules in a dimer, so the molar mass found in benzene is near double.

The worked solution

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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

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