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For two events, P(A) = 0.45 and P(B) = 0.35…

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Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

For two events, $P(A) = 0.45$ and $P(B) = 0.35$ . The probability that neither happens is $0.3$ . Find $P(A \cup B)$ and $P(A \cap B)$ . Then find the probability that exactly one of the two events happens. Are $A$ and $B$ mutually exclusive?

Need a reminder? The key ideaShow

$P(\text{not } A) = 1 - P(A)$ . For any two events $P(A \cup B) = P(A) + P(B) - P(A \cap B)$ . If $A$ and $B$ are mutually exclusive, the overlap is $0$ .

The worked solution

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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

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