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  1. Problems
  2. /Find the respiratory quotient from the equation…
EasyBiologyHigh School (11–12)Plant Biology › Respiration in PlantsNumericalA-LevelAPIB

Find the respiratory quotient from the equation…

StemPy LabContributed by StemPy Lab

Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

Find the respiratory quotient from the equation.

  1. C6H12O6+6 O2⟶6 CO2+6 H2O\text{C}_6\text{H}_{12}\text{O}_6 + 6\,\text{O}_2 \longrightarrow 6\,\text{CO}_2 + 6\,\text{H}_2\text{O}C6​H12​O6​+6O2​⟶6CO2​+6H2​O
  1. 2 (COOH)2+O2⟶4 CO2+2 H2O2\,(\text{COOH})_2 + \text{O}_2 \longrightarrow 4\,\text{CO}_2 + 2\,\text{H}_2\text{O}2(COOH)2​+O2​⟶4CO2​+2H2​O
  1. Which of the two is a carbohydrate, and which is an organic acid?

Check your answer

Work it out on paper, then type your number. The answer itself stays hidden.

Need a reminder? The key ideaShowHide

RQ=volume of CO2 releasedvolume of O2 taken in\text{RQ} = \dfrac{\text{volume of CO}_2\ \text{released}}{\text{volume of O}_2\ \text{taken in}}RQ=volume of O2​ taken involume of CO2​ released​. It is 111 for carbohydrate, about 0.90.90.9 for protein, 0.70.70.7 for fat, and above 111 for organic acids. KOH takes in carbon dioxide, so the fall of volume in a tube with KOH is the oxygen taken in.

The worked solution

Have you tried it?

Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

Step 1. (a) RQ=66=1\text{RQ} = \dfrac{6}{6} = 1RQ=66​=1.

Step 2. (b) RQ=41=4\text{RQ} = \dfrac{4}{1} = 4RQ=14​=4.

Step 3. (c) Glucose is a carbohydrate. Oxalic acid is an organic acid.

Answer: 111 for glucose; 444 for oxalic acid. The organic acid has the RQ above 111.

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  1. The respiratory quotientBalance Sheet, Amphibolic Pathway and Respiratory Quotient

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