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Find the pH of 0.0002 M hydrochloric acid and of 0.0005 M sodium hydroxide.

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Find the pH of $0.0002\ \text{M}$ hydrochloric acid and of $0.0005\ \text{M}$ sodium hydroxide. Both are strong. Use $\text{pH} = -\log_{10}[\text{H}^+]$ and $\text{pH} + \text{pOH} = 14$ .

Need a reminder? The key ideaShow

pH runs from $0$ to $14$ : below $7$ acidic, $7$ neutral, above $7$ basic. $\text{pH} = -\log_{10}[\text{H}^+]$ , so for $10^{-n}\ \text{M}$ the pH is $n$ , and one step is a factor of ten. For bases, pH $= 14 -$ pOH. Diluting a strong acid ten times raises its pH by $1$ .

The worked solution

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Find the pH of 0.0002 M hydrochloric acid and of 0.0005 M sodium hydroxide.

The worked solution

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