Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Find the oxidation number of (a) phosphorus in ; (b) chlorine in ; (c) manganese in ; (d) sulfur in .
Oxidation numbers: free element 0; simple ion its charge; F is -1; H is +1 (in metal hydrides -1); O is -2 (peroxides -1, superoxides -1/2, in OF2 +2); alkali metals +1, alkaline earth metals +2. The numbers add up to the charge of the species. A rise is oxidation, a fall is reduction.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. (a). , so .
Step 2. (b). , so .
Step 3. (c). , so .
Step 4. (d). , so .
Answer: , , and .
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