Find the average translational kinetic energy of a molecule of a gas at 27 °C and at 327 °C…

Step 1. Kelvin. $27\ ^\circ\text{C} = 300$ K and $327\ ^\circ\text{C} = 600$ K.

Step 2. At 300 K. $\bar{K} = \tfrac32 \times 1.38 \times 10^{-23}\ \text{J/K} \times 300\ \text{K} = 6.21 \times 10^{-21}$ J.

Step 3. At 600 K. $\bar{K} = \tfrac32 \times 1.38 \times 10^{-23}\ \text{J/K} \times 600\ \text{K} = 1.24 \times 10^{-20}$ J.