Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Write the electron configurations of silicon (), vanadium () and manganese (), using the short form with a noble gas. How many unpaired electrons does each have?
Aufbau, Pauli and Hund fill the orbitals. Chromium and copper move one electron into . Ions lose electrons before . Spin-only magnetic moment: for unpaired electrons.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Silicon. : two single electrons, so unpaired.
Step 2. Vanadium. : three single electrons, so unpaired.
Step 3. Manganese. : five single electrons, so unpaired.
Answer: as above, with , and unpaired electrons.
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