Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Chlorine reacts with cold dilute alkali: . It reacts with hot concentrated alkali: . Find the oxidation number of chlorine in each oxidised product. Then, for the hot reaction, find how many chlorine atoms are reduced for each one oxidised.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. . , so .
Step 2. . , so .
Step 3. Electrons in the hot reaction. An atom going from 0 to loses 5 electrons. An atom going from 0 to gains 1 electron.
Step 4. The ratio. To gain 5 electrons, 5 atoms must be reduced for each atom oxidised. This matches for each .
Answer: , , and 5 atoms reduced for each one oxidised.
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Five kinds: combination, decomposition, displacement, disproportionation (one element goes up and down) and comproportionation (two states of one element become one). If no oxidation number changes, it is not a redox reaction.