Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Chlorine reacts with cold dilute alkali: . It reacts with hot concentrated alkali: . Find the oxidation number of chlorine in each oxidised product. Then, for the hot reaction, find how many chlorine atoms are reduced for each one oxidised.
Five kinds: combination, decomposition, displacement, disproportionation (one element goes up and down) and comproportionation (two states of one element become one). If no oxidation number changes, it is not a redox reaction.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. . , so .
Step 2. . , so .
Step 3. Electrons in the hot reaction. An atom going from 0 to loses 5 electrons. An atom going from 0 to gains 1 electron.
Step 4. The ratio. To gain 5 electrons, 5 atoms must be reduced for each atom oxidised. This matches for each .
Answer: , , and 5 atoms reduced for each one oxidised.
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