Ethanol burns as C₂H₅OH + 3 O₂ → 2 CO₂ + 3 H₂O.

Step 1. Moles of ethanol. $69\ \text{g} \div 46\ \text{g/mol} = 1.5\ \text{mol}$.

Step 2. Oxygen. $3 \times 1.5 = 4.5\ \text{mol}$, which is $4.5 \times 32 = 144\ \text{g}$.

Step 3. Carbon dioxide. $2 \times 1.5 = 3\ \text{mol}$, which is $3 \times 44 = 132\ \text{g}$.

Step 4. Water. $3 \times 1.5 = 4.5\ \text{mol}$, which is $4.5 \times 18 = 81\ \text{g}$.