Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
Benzo[a]pyrene has the formula and a molar mass of . The mass of carbon in one mole is . It forms when organic matter burns without enough air. The carbon dioxide has a molar mass of .
Find the percentage of carbon in benzo[a]pyrene and the mass of carbon dioxide formed when of it burns completely. Compare the percentage with for benzene.
A group on the ring directs the next substituent. , and alkyl groups activate and direct ortho and para. Halogens deactivate and direct ortho and para. , , , and deactivate and direct meta. Light and heat attack the side chain. A Lewis acid in the dark attacks the ring.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Percentage. .
Step 2. Moles. .
Step 3. Carbon dioxide. .
Step 4. Compare. is higher than . Compounds with larger fused rings are richer in carbon, so they burn with even more soot.
Answer: and .
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