An FM radio station broadcasts at a frequency of 94.3 MHz…

Step 1. The wavelength. $\lambda = \dfrac{c}{f} = \dfrac{3.00 \times 10^{8}\ \text{m/s}}{94.3 \times 10^{6}\ \text{Hz}} = 3.18\ \text{m}$.

Step 2. The time of one cycle. $T = \dfrac{1}{f} = \dfrac{1}{94.3 \times 10^{6}\ \text{Hz}} = 10.6\ \text{ns}$.

Step 3. The photon energy. $E = hf = 4.14 \times 10^{-15}\ \text{eV s} \times 94.3 \times 10^{6}\ \text{Hz} = 3.90 \times 10^{-7}\ \text{eV}$.