Two displacements are A = (2î - 5ĵ) m and B = (-4î + 3ĵ) m.

Step 1. The sum. $\vec{A} + \vec{B} = (2 - 4)\hat{i} + (-5 + 3)\hat{j} = (-2\hat{i} - 2\hat{j})\ \text{m}$. Its size is $\sqrt{(2\ \text{m})^2 + (2\ \text{m})^2} = 2.83\ \text{m}$.

Step 2. Its direction. Both parts are negative, so it points down and to the left. The angle with the $x$ axis is $\tan^{-1} 1 = 45^\circ$, so from $+x$ it is $180^\circ + 45^\circ = 225^\circ$.

Step 3. The difference. $\vec{A} - \vec{B} = (2 + 4)\hat{i} + (-5 - 3)\hat{j} = (6\hat{i} - 8\hat{j})\ \text{m}$. Its size is $\sqrt{(6\ \text{m})^2 + (8\ \text{m})^2} = 10\ \text{m}$.

Step 4. Its direction. The $x$ part is positive and the $y$ part negative: down and to the right. The angle below $+x$ is $\tan^{-1}\dfrac{8}{6} = 53.1^\circ$, so from $+x$ it is $360^\circ - 53.1^\circ = 306.9^\circ$.