A zeolite has the formula Na₁₂[(AlO₂)₁₂(SiO₂)₁₂]· 27H₂O and a molar mass of 2191 g/mol…

A zeolite has the formula $\text{Na}_{12}[(\text{AlO}_{2})_{12}(\text{SiO}_{2})_{12}]\cdot 27\text{H}_{2}\text{O}$ and a molar mass of $2191\ \text{g/mol}$. Hard water holds $160\ \text{mg}$ of calcium ions in each litre. Each calcium ion takes the place of two sodium ions of the zeolite. Take $M(\text{Ca}) = 40.08\ \text{g/mol}$ and $M(\text{Na}) = 22.99\ \text{g/mol}$. Find the mass of calcium that $1.00\ \text{g}$ of the zeolite can remove. Then find the mass of zeolite needed to soften $1000\ \text{L}$ of the water, and the mass of sodium that goes into the water.