Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A works wants of potassium dichromate, , which has a molar mass of . The ore holds chromite, , by mass. The molar mass of chromite is . Only of the chromium in the ore ends up in the dichromate. Each formula unit of chromite and each of dichromate holds 2 chromium atoms. Find the moles of dichromate wanted, the mass of pure chromite needed and the mass of ore.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Dichromate wanted. .
Step 2. Chromite, with the yield. One chromite unit gives one dichromate unit, since each holds 2 chromium atoms. At an 80.0 % yield, of chromite is needed. The mass is .
Step 3. The ore. The ore is 56.0 % chromite, so .
Answer: , and of ore.
Watch out. A yield of less than 100 % means more raw material, so divide by it. Do not multiply.
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Moles = mass in g divided by molar mass in g/mol, or concentration in mol/L times volume in litres. Take every mole ratio from the balanced equation, and follow the chain one step at a time.