A wire 0.15 m long carries 8 A at right angles to a field of 0.45 T…

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Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

A wire $0.15\ \text{m}$ long carries $8\ \text{A}$ at right angles to a field of $0.45\ \text{T}$ . Find the force on it. What is the force when the wire is turned to make $30^\circ$ with the field?

Need a reminder? The key ideaShow

A wire with a current in a magnetic field feels a force $F = BIL\sin\theta$ , where $\theta$ is the angle between the wire and the field. It is largest ( $F = BIL$ ) at right angles, and zero along the field. Fleming's left-hand rule: forefinger for the field, middle finger for the current, thumb for the force.

The worked solution

Have you tried it?

Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

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