A toy is a cone of height 8 cm standing on a hemisphere…

Step 1. The slant height. $l = \sqrt{6^2 + 8^2}\ \text{cm} = 10\ \text{cm}$.

Step 2. The cone. $\pi r l = \pi \times 6\ \text{cm} \times 10\ \text{cm} = 60\pi\ \text{cm}^2$.

Step 3. The hemisphere. $2\pi r^2 = 2\pi \times (6\ \text{cm})^2 = 72\pi\ \text{cm}^2$.

Step 4. The total. $60\pi + 72\pi = 132\pi\ \text{cm}^2$, which is $414.7\ \text{cm}^2$ to one decimal place.