Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A thin biconvex lens of glass with refractive index has a focal length of in air. A teacher dips it, in turn, in water of refractive index and in a dense oil of refractive index . The lens is held with its axis along a laser beam that is wide and parallel. Find the focal length of the lens in the water and in the oil, and the power of the lens in the oil, in dioptre. Say whether the oil lens converges or diverges the beam, and say in which liquid of what refractive index the lens would have no effect at all.
With the object and the screen apart, a lens that gives a sharp image at two positions apart has . The two magnifications are and , so . In a liquid, . With two different media, and .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. and .
Plan. The factor replaces in the lens maker's formula. We divide the formula in the liquid by the formula in air.
Step 1. Water. . So .
Step 2. Oil. . So , more exactly .
Step 3. The power in the oil. . The negative sign means that the lens diverges the beam.
Step 4. The liquid with no effect. The bracket is zero when . The focal length is infinite.
Answer: , and . The oil lens diverges the beam, and a liquid of index makes the lens do nothing.
Check. The lens is weaker in water than in air: is longer than . In oil it changes sign, as it must when .
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