Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A survey asks students how many hours they play video games in a week. The answers are grouped, and the last class is open, because a few students would not give an upper limit. The school wants one typical number to report, and it asks which of the three averages it is able to find from the table at all. Decide, and then find the ones that can be found.
| Hours | Students |
|---|---|
| 0-5 | 8 |
| 5-10 | 15 |
| 10-15 | 12 |
| 15-20 | 4 |
| 20 and above | 1 |
Which of the mean, the median and the mode can be found from the table? Find those that can.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. The mean. The last class has no upper end, so it has no class mark. The mean cannot be found.
Step 2. The median. The cumulative frequencies are , and . The median class is to , with and . Then hours.
Step 3. The mode. The modal class is to , with , and . Then hours.
Answer: the mean cannot be found. The median is hours and the mode is hours.
What do you notice? The one student in the open class does not change the median or the mode, however many hours that student plays. That is why the median is a good average for data with an open last class.
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For a moderately skewed table, . It is an approximation only. With an open last class the mean cannot be found, but the median and the mode can be, when their classes are not the open class.