Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A student weighs of pure potassium dichromate, with a molar mass of . It is dissolved, and acid and excess potassium iodide are added: . The iodine that forms needs of sodium thiosulfate solution, by . Find the amount of dichromate, the amount of iodine and the concentration of the thiosulfate solution.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Dichromate. .
Step 2. Iodine. The first equation gives , so .
Step 3. Thiosulfate. The second equation gives , so .
Step 4. Concentration. .
Answer: , and .
Check. One dichromate ion matches 6 thiosulfate ions, and .
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Moles = mass in g divided by molar mass in g/mol, or concentration in mol/L times volume in litres. Take every mole ratio from the balanced equation, and follow the chain one step at a time.