Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A student joins a zinc half-cell to a standard hydrogen electrode. The voltmeter reads and the zinc is the negative terminal. (a) Name the conditions for the zinc half-cell and for the hydrogen electrode. (b) Write the sign and size of for and explain it.
is a reduction potential, measured against the standard hydrogen electrode, which is , at , and . . Reversing a half-reaction changes the sign of . Multiplying it changes nothing.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
(a) Conditions. The zinc ions are at . The hydrogen electrode is platinum in at with hydrogen gas at . Both are at .
(b) The value. Electrons flow from zinc to the hydrogen electrode, so zinc gives up electrons more readily than hydrogen does. The hydrogen electrode is by agreement. So .
Answer: . The negative sign means zinc is the better electron donor.
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