Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A student heats of anisole with excess concentrated hydrogen iodide. The yield of each product is . Use for anisole, for phenol and for iodomethane. Find the mass of phenol and the mass of iodomethane. Then say what a further molecule of HI does to the phenol.
HI cleaves the C-O bond. Iodide attacks the less crowded carbon (or the tertiary one). An aryl C-O bond stays, so an aryl alkyl ether gives a phenol and an alkyl iodide. Excess HI turns an alkyl ether into two alkyl iodides. The net dipole of two bond dipoles at angle is .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. of anisole, yield.
Step 1. Anisole. .
Step 2. Phenol. .
Step 3. Iodomethane. .
Step 4. More HI. Nothing happens to the phenol. An attack on an ring carbon cannot occur, so iodobenzene does not form.
Check. One mole of anisole gives one mole of each product, so the ratio of the masses is the ratio of the molar masses: , and .
Answer: and .
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