Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A step-down transformer is efficient at full load. At full load the secondary gives A at V. The primary is joined to the V mains. Find the power given out, the power taken in, the current in the primary and the power lost as heat.
For an ideal transformer, and the power in equals the power out, , so . For a real one, the efficiency is , and is plus the losses.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. , V, A and V.
Step 1. The power out. W.
Step 2. The power in. We want , so W.
Step 3. The primary current. A.
Step 4. The power lost. W.
Answer: W, W, A and W.
What if? An ideal transformer would take A. The real one takes A. The extra current feeds the W of heat.
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