A spinner shows 1, 2 or 6, each with the same chance…

Step 1. The population. The mean is $3$. The squared distances are $4$, $1$ and $9$, so the variance is $\dfrac{14}{3} \approx 4.667$.

Step 2. The sample means. Their mean is $3$. Their squared distances from $3$ add up to $21$, so their variance is $\dfrac{21}{9} = \dfrac{7}{3} \approx 2.333$.

Step 3. Compare. $\dfrac{14/3}{7/3} = 2$.

What it means. The variance of a mean of $2$ independent spins is the population variance divided by $2$. That is the rule $SE = \dfrac{\sigma}{\sqrt{n}}$, squared.