EasyMathematicsHigh School (9–10)Mensuration › Areas and PerimetersNumericalBoard Exam

A sector of a circular garden has a radius of 28 m and an angle of 45°…

Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

A sector of a circular garden has a radius of $28\ \text{m}$ and an angle of $45^\circ$ . Find its area. Take $\pi = \dfrac{22}{7}$ .

Need a reminder? The key ideaShow

A sector with angle $\theta$ has area $\dfrac{\theta}{360}\pi r^2 = \dfrac{1}{2}\,l\,r$ . The minor and the major sector add up to the whole circle. A blade between radii $r$ and $R$ sweeps $\dfrac{\theta}{360}\pi(R^2 - r^2)$ .

The worked solution

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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

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