A sample of 5.43 g of mercury(II) chloride (271.49 g/mol) is reduced by tin(II) chloride (189.61…

A sample of $5.43\ \text{g}$ of mercury(II) chloride ($271.49\ \text{g/mol}$) is reduced by tin(II) chloride ($189.61\ \text{g/mol}$). First white calomel forms: $2\text{HgCl}_{2} + \text{SnCl}_{2} \to \text{Hg}_{2}\text{Cl}_{2} + \text{SnCl}_{4}$. Then more tin(II) chloride turns it into grey mercury: $\text{Hg}_{2}\text{Cl}_{2} + \text{SnCl}_{2} \to 2\text{Hg} + \text{SnCl}_{4}$. Use $472.08\ \text{g/mol}$ for calomel and $200.59\ \text{g/mol}$ for mercury. Find the mass of calomel, the mass of tin(II) chloride for the first step, the mass of mercury at the end and the total mass of tin(II) chloride used.