A sample of 200 plants has 90 AA, 60 Aa and 50 aa individuals…
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
A sample of 200 plants has 90 , 60 and 50 individuals. They all take part in random mating for one generation, and the next generation also has 200 plants.
- What is the frequency of the allele in the sample?
- How many plants are expected in the next generation?
- How many plants are expected in the next generation?
- What is in the next generation?
Need a reminder? The key ideaShow
Count gene copies: each individual has two. The frequencies of two alleles add up to 1. At equilibrium the genotypes are . Start from the recessive trait, which shows . The five factors that disturb the equilibrium are gene flow, drift, mutation, recombination and selection.
The worked solution
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. , , , a total of plants.
Plan. Count alleles in the sample. Apply , and to the next generation.
Step 1. (a) Copies of : of . , and .
Step 2. (b) . plants.
Step 3. (c) . plants. The plants are .
Step 4. (d) Copies of : of , so again.
Answer: ; plants; plants; stays .
Check. . The genotype counts changed, but the allele frequency did not. This is the Hardy-Weinberg principle.
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