A rubber mounting pad is 4.0 cm thick with a face of 150 cm²…

Step 1. Stress. $\dfrac{30\ \text{N}}{0.015\ \text{m}^2} = 2000\ \text{Pa}$.

Step 2. Angle. $\dfrac{2000\ \text{Pa}}{4.0 \times 10^{5}\ \text{Pa}} = 5.0 \times 10^{-3}\ \text{rad}$.

Step 3. Shift. $5.0 \times 10^{-3} \times 0.040\ \text{m} = 2.0 \times 10^{-4}\ \text{m}$.