A uniform rod has a mass of 3.2 kg and a length of 1.5 m…

Step 1. (a) $d = 0.75\ \text{m}$: $0.60\ \text{kg\,m}^2 + 3.2\ \text{kg} \times 0.5625\ \text{m}^2 = 2.4\ \text{kg m}^2$, which is $\tfrac13 ML^2$.

Step 2. (b) $d = 0.25\ \text{m}$: $0.60\ \text{kg\,m}^2 + 3.2\ \text{kg} \times 0.0625\ \text{m}^2 = 0.80\ \text{kg m}^2$.