Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A red LED is made from a semiconductor of band gap eV, and a blue LED from a semiconductor of band gap eV. Take the photon energy as the band gap, with . Find the wavelength of the light of each. The blue LED drops V when it works at mA. Find the series resistor that it needs on a supply of V.
An LED gives light of wavelength , with , and needs a series resistor . A photodiode with a share of photons counted gives for light of power and photon energy in eV. A solar cell gives and has the efficiency .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Red. nm.
Step 2. Blue. nm.
Step 3. The resistor. .
Answer: nm, nm and .
Check. The red LED has the smaller gap and the longer wavelength. The blue LED has the larger gap and the shorter wavelength. A blue LED also needs a larger drop, so its resistor is smaller.
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