A rectangular coil has 120 turns. Each turn is 2.0 cm by 4.5 cm…

Step 1. The area. $A = 2.0 \times 4.5\ \text{cm}^2 = 9.0\ \text{cm}^2 = 9.0 \times 10^{-4}\ \text{m}^2$.

Step 2. The moment. $m = NIA = 120 \times 0.80\ \text{A} \times 9.0 \times 10^{-4}\ \text{m}^2 = 0.0864\ \text{A m}^2$.

Step 3. The angle. The normal is at $90^\circ$ to the plane. So the angle between the normal and the field is $\theta = 90^\circ - 25^\circ = 65^\circ$.

Step 4. The torque. $\tau = mB\sin\theta = 0.0864\ \text{A m}^2 \times 0.35\ \text{T} \times \sin 65^\circ = 0.0274\ \text{N m}$.