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A reaction has an activation energy of 64 kJ/mol…

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Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

A reaction has an activation energy of $64\ \text{kJ/mol}$ . Find the number $\dfrac{E_a}{RT}$ at $350\ \text{K}$ and at $360\ \text{K}$ . By what factor does the share of molecules with enough energy grow?

Need a reminder? The key ideaShow

The share of molecules with enough energy is $e^{-E_a/RT}$ . The rate constant is $k = P\,Z\,e^{-E_a/RT}$ , so $A = PZ$ . For the energy profile, $\Delta H = E_a - E_a'$ , where $E_a'$ is the barrier of the reverse reaction.

The worked solution

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Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

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