Find the point on the y-axis that is equally far from A(5, 1) and B(-3, 5). How far is it from each?

Step 1. The equation. $25 + (y - 1)^2 = 9 + (y - 5)^2$.

Step 2. Expand. $26 - 2y + y^2 = 34 - 10y + y^2$, so $8y = 8$ and $y = 1$.

Step 3. The distance. From $(0, 1)$ to $A$: $\sqrt{25 + 0} = 5$ units. To $B$: $\sqrt{9 + 16} = 5$ units.