Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A plant with round yellow seeds is crossed with a plant with round green seeds. R (round) is dominant over r (wrinkled), and Y (yellow) is dominant over y (green). The offspring are:
Genes on different chromosomes assort independently, so you can multiply the chances of the separate genes. RrYy × RrYy gives 9 round yellow : 3 round green : 3 wrinkled yellow : 1 wrinkled green. A plant heterozygous for genes makes kinds of gamete, and its F2 has genotypes.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. Round yellow × round green. Offspring in the ratio .
Plan. Split the cross into two single gene crosses.
Step 1. Shape. Round is parts and wrinkled is parts, a ratio of . So both parents are Rr.
Step 2. Colour. Yellow is parts and green is parts, a ratio of . The green parent is yy, so the yellow parent is Yy.
Step 3. (a) The round yellow parent is RrYy and the round green parent is Rryy.
Step 4. (b) RrYy makes RY, Ry, rY and ry. Rryy makes Ry and ry.
Step 5. (c) Wrinkled is of the offspring.
Answer: (a) RrYy × Rryy; (b) four kinds of gamete and two kinds; (c) one quarter.
Check. The ratio of RrYy × Rryy is for round yellow, which is , that is parts out of .
Watch out. A ratio of is not a dihybrid test cross. It comes from one heterozygous pair and one test cross pair.
Log in to join the discussion.
Loading…
With Standard, you also open 12 more problems, 2 Python labs and 1 extra course. Everything you have used here stays free, always.