Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A market stall records the number of minutes that its customers spend at the stall. The class marks are and minutes, and the frequencies are and . Two frequencies were lost. The stall owner knows that there were customers and that the mean time was minutes.
Name the missing frequency , write the clue as a formula in , solve, and check. For the mean, use with both and in terms of . For the median, decide the median class first. A frequency is a whole number that is not negative.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. The total. gives .
Step 2. The sum. . It equals , so , which is .
Step 3. Solve. From we get . Subtract from : , so and .
Part (b). For the mean , , so , which is . With we get , so . A frequency cannot be negative or a fraction, so no such table exists.
Answer: and . A mean of is impossible for this table.
Check. , and .
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