Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A hexose (molar mass ) is treated with excess acetic anhydride. A sample of of the sugar gives of the acetylated product, with every reactive group changed to . Each change replaces an H atom by a group and adds . Find how many groups the sugar has.
A carbohydrate is a polyhydroxy aldehyde or ketone. An aldose has stereocentres and a ketose has , where is the number of carbons in the chain. The number of stereoisomers is , and half of them belong to the D series. An empirical formula comes from the moles of each element in 100 g.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Plan. Each acetylated adds a fixed mass. Divide the mass gained per mole by it.
Step 1. Amount of the sugar. .
Step 2. Mass gained. . For one mole: .
Step 3. Groups. .
Answer: the sugar has 5 hydroxyl groups, so it makes a pentaacetate.
Check. The pentaacetate has a molar mass of , and glucose pentaacetate is with .
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