A clean glass tube of radius 0.40 mm is dipped in water and tilted at 45° to the vertical…

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Try it on paper first. A hint, the key idea and the worked solution are here when you need them.

A clean glass tube of radius $0.40\ \text{mm}$ is dipped in water and tilted at $45^\circ$ to the vertical. How high, measured straight up, does the water rise? How long is the column of water along the tube? (Surface tension $0.072\ \text{N/m}$ , angle of contact $0^\circ$ , $g = 9.8\ \text{m/s}^2$ .)

Need a reminder? The key ideaShow

Capillary rise: $h = \dfrac{2S\cos\theta}{\rho gr}$ , where $\theta$ is the angle of contact. A liquid that wets the tube ( $\theta < 90^\circ$ ) rises; one that does not ( $\theta > 90^\circ$ ) is pushed down.

The worked solution

Have you tried it?

Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.

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