Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A glass artist designs a window panel. Seen from the front, the lead outline follows the curve , where and are in decimetres. The curve meets the horizontal base line, the -axis, at three points. Two regions of glass lie between the curve and the base line: a small region on the left and a large region on the right. The small region uses red glass at rupees per square decimetre. The large region uses blue glass at rupees per square decimetre. A customer asks for the area of each region and the total cost of the glass. The glass comes in sheets, and the artist has marked the two regions in different colours on her drawing, so that the cutter can price each one separately. Find the area of the small region, the area of the large region and the total cost.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. The zeros. at , and . The small region lies between and , and the large region lies between and .
Step 2. The antiderivative. . Then , and .
Step 3. The small region. The integral from to is , which is positive. The area is square decimetres.
Step 4. The large region. The integral from to is , so the curve is below the axis. The area is square decimetres.
Step 5. The cost. Red glass: rupees. Blue glass: rupees. The total is rupees.
Answer: square decimetres, square decimetres and rupees.
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The integral gives a signed area. For the total area, find the zeros of inside the interval, integrate over each piece and add the absolute values of the results.