Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A gardener plants seeds of a made-up variety, a random sample from a large batch, and of them sprout late. Check the conditions. Find the 95% interval for the share of all the seeds in the batch that sprout late. Give the standard error and the margin to four decimal places, and the ends to three.
The interval for a proportion is . It needs a random sample with at least successes and failures. For a margin , .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. Conditions. The seeds are a random sample. There are successes and failures, both at least . The batch is large.
Step 2. Standard error. .
Step 3. Margin. .
Step 4. Interval. From to .
Answer: , , and from to .
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