Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A gardener crosses a true-breeding tall pea plant with a true-breeding dwarf plant. She lets the F1 plants pollinate themselves and grows F2 plants. Tall (T) is dominant over dwarf (t).
In a monohybrid cross with complete dominance, the F1 of TT × tt is all Tt and tall. The F2 has the genotypic ratio 1 TT : 2 Tt : 1 tt and the phenotypic ratio 3 tall : 1 dwarf. A test cross uses a homozygous recessive partner (tt). A Tt parent gives T and t with equal chance, so each child of two carriers has a chance of of showing the recessive trait.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. F2 of plants from the F1 genotype Tt × Tt.
Plan. Use the phenotypic ratio and the genotypic ratio .
Step 1. Tall plants. Three parts out of four are tall: plants.
Step 2. Dwarf plants. One part out of four: plants.
Step 3. Tall plants that breed true. Only TT plants breed true. TT is one part out of four of the F2: plants. The other tall plants are Tt, and they give dwarf plants as well.
Answer: tall plants; dwarf plants; of the tall plants breed true.
Check. , and the tall plants are TT and Tt.
Watch out. Do not say that all tall plants breed true. Two thirds of them are heterozygous.
Log in to join the discussion.
Loading…
With Standard, you also open 12 more problems, 2 Python labs and 1 extra course. Everything you have used here stays free, always.