The pointer of a galvanometer turns 80° for a full-scale current of 40 mA, and the turn is…

Step 1. Each milliampere. $\dfrac{80^\circ}{40\ \text{mA}} = 2^\circ$ for each milliampere.

Step 2. (a) $2^\circ \times 25 = 50^\circ$.

Step 3. (b) $\dfrac{32^\circ}{2^\circ\ \text{per mA}} = 16\ \text{mA}$.