Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A flask holds bacteria that contain 4 heavy DNA molecules in all (15N in both strands of each). The bacteria are moved to a medium with 14N, and they grow without any loss until they have divided 5 times. Count the DNA molecules, and ignore the other chromosomes of the cells.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. heavy molecules, generations.
Plan. Double the number five times. Find the hybrids from the number of old strands.
Step 1. (a) molecules.
Step 2. (b) The starting molecules have old strands. Each old strand is in a different molecule, so there are hybrid molecules.
Step 3. (c) light molecules.
Step 4. (d) .
Answer: ; ; ; .
Check. The share is the same, because the number of starting molecules cancels.
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In semiconservative replication, each new double helix has one old strand and one new strand. After generations in a light medium, of the molecules are hybrid, and the rest are light. After one generation the tube shows one band in the middle. After two generations it shows a hybrid band and a light band in equal amounts.
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