A fit with curve_fit gives an amplitude of 0.80 m…
Contributed by StemPy LabTry it on paper first. A hint, the key idea and the worked solution are here when you need them.
A fit with curve_fit gives an amplitude of m. The first number on the diagonal of pcov is m. What is the error of the amplitude? What percent of m is it?
Need a reminder? The key ideaShow
np.fft.rfftfreq(n, d) gives frequencies apart, and the tallest bar of np.abs(np.fft.rfft(y)) is the main frequency. A reading rate can show frequencies up to ; above that a wave aliases to . curve_fit returns popt and pcov, and the errors are np.sqrt(np.diag(pcov)).
The worked solution
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. The error. pcov holds squares, so m.
Step 2. The percent. %.
Step 3. Report it. The amplitude is m.
Answer: m, which is % of the amplitude.
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