Masses of 1.5 kg and 2.5 kg are fixed to the ends of a light rod 1.2 m long…

Step 1. (a) $2.5\ \text{kg} \times (1.2\ \text{m})^2 = 3.6\ \text{kg m}^2$.

Step 2. (b) $1.5\ \text{kg} \times (1.2\ \text{m})^2 = 2.16\ \text{kg m}^2$.

Step 3. (c) Distances $0.75\ \text{m}$ and $0.45\ \text{m}$: $1.5\ \text{kg} \times 0.5625\ \text{m}^2 + 2.5\ \text{kg} \times 0.2025\ \text{m}^2 = 0.844\ \text{kg\,m}^2 + 0.506\ \text{kg\,m}^2 = 1.35\ \text{kg m}^2$.