Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A designer draws a parabola whose focus is the point and whose directrix is the line . Find the value of , the -coordinate of the vertex, and the length of the latus rectum. Write the equation in the form and check that the point is on it.
The parabola has its focus at and its directrix . The latus rectum has length , and the focal distance of is . The point is on it for every .
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Step 1. The distance. The focus is at height and the directrix at height , so they are units apart. This is , so .
Step 2. The vertex. It is halfway between: . The vertex is .
Step 3. The latus rectum. .
Step 4. The equation. gives .
Check. At : , yes. Its distance from the focus is and from the directrix is .
Answer: , the vertex has and the latus rectum is .
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