Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A curve in the plane has the property that its slope at every point is three times the height of the point above the -axis, so . The curve is above the axis and passes through the point . Find the height of the curve at , and find the value of at which the height is . Give both answers to four decimal places.
A separable equation becomes . Integrate both sides with one constant, then use the point.
The zeros of give constant solutions.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. , , and at .
Plan. Separate the variables, integrate, fix the constant, then evaluate.
Step 1. Separate and integrate. gives , so .
Step 2. The constant. At : . The curve is .
Step 3. The height at . .
Step 4. Where the height is . gives , so and .
Answer: at , and at .
Check. The slope at is , a steep curve, as the quick growth from to in half a unit suggests.
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