Try it on paper first. A hint, the key idea and the worked solution are here when you need them.
A circular plasmid of bp is cut with one enzyme. The gel shows a band at bp, a band at bp and a band at bp that is twice as bright as the others.
Read a size from a ladder with a straight line of size against distance. An uncut plasmid shows a supercoiled band (fastest), a linear band and a nicked band (slowest). The control plates are: no DNA, uncut vector, cut vector without ligase, and cut vector with ligase and no insert. Efficiency colonies (ng of DNA on the plate) for each microgram.
Have you tried it?
Work it out on paper first. It is fine to get stuck or make a mistake: that is how we learn. When you are ready, go through the solution one step at a time, and check each step against your own.
Given. Plasmid bp. Bands , and bp, the last one twice as bright.
Plan. The fragments of a digest must add up to the plasmid.
Step 1. (a) bp.
Step 2. (b) bp are missing.
Step 3. (c) The missing bp is a second fragment of bp, which runs together with the first one in a brighter band. So there are four fragments: , , and bp. A circle with four fragments has sites.
Answer: bp; bp; two equal fragments in the bright band, and four sites.
Check. bp.
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