A circular loop has a radius of 5.0 cm. It is in a uniform field of 0.60 T…

Step 1. The area. $A = \pi r^2 = \pi \times (0.050\ \text{m})^2 = 7.85 \times 10^{-3}\ \text{m}^2$.

Step 2. The three fluxes.

• At $0^\circ$: $\Phi = BA = 0.60\ \text{T} \times 7.85 \times 10^{-3}\ \text{m}^2 = 4.71 \times 10^{-3}\ \text{Wb}$, that is $4.71$ mWb.
• At $60^\circ$: $\Phi = 4.71\ \text{mWb} \times \cos 60^\circ = 2.36$ mWb.
• At $180^\circ$: $\Phi = 4.71\ \text{mWb} \times \cos 180^\circ = -4.71$ mWb.