A circuit has R = 24 Ω and a net reactance of 32 Ω…

Step 1. The impedance. $Z = \sqrt{(24\ \Omega)^2 + (32\ \Omega)^2} = 40\ \Omega$.

Step 2. The current. $I_{rms} = \dfrac{120\ \text{V}}{40\ \Omega} = 3$ A.

Step 3. The power factor. $\cos\phi = \dfrac{R}{Z} = \dfrac{24\ \Omega}{40\ \Omega} = 0.6$.

Step 4. The powers. The average power is $P = V_{rms}I_{rms}\cos\phi = 120\ \text{V} \times 3\ \text{A} \times 0.6 = 216$ W. The apparent power is $120\ \text{V} \times 3\ \text{A} = 360$ VA.